What is the end behavior of the function f(x) = -3x4-x3 + 2x2 + 4x + 5? -up on the left, up on the right -up on the left, down on the right -down on the left, up on the right -down on the left, down on the right
it would be up and up right?
I see right away that your function is of the 4th order. If the coefficient of the x^4 term is +, the curve will open upward; it starts in the 2nd quadrant and ends in the 1st quadrant. Hope this language is familiar for you.
On the other hand, if the coeff of the x^4 term is (-), the curve will open downward; it starts in Q3 and ends in Q4. In otherwords up on the left and down on the right. Draw it.
Please open this in your browser: https://www.google.com/search?q=f(x)+%3D+-3x%5E4-x%5E3+%2B+2x%5E2+%2B+4x+%2B+5&rlz=1C1CHFX_enUS461US461&oq=f(x)+%3D+-3x%5E4-x%5E3+%2B+2x%5E2+%2B+4x+%2B+5&aqs=chrome..69i57.20178j0j7&sourceid=chrome&espv=210&es_sm=122&ie=UTF-8
Sorry, Molly, but it's 'way past my usual bedtime, and so I'm heading upstairs. Do ask (perhaps through a message) if you have additional questions about this problem. Good night!
Okay thanks!
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