What is the equation of the line that contains the points (3, –6) and (–3, 0)?
A. y = x – 3 B. y = –x – 3 C. y = –x + 3 D. y = x + 3
lets find the slope first slope(m) = (y2 - y1) / (x2 - x1) (3,-6) x1 = 3 and y1 = -6 (-3,0) x2 = -3 and y2 = 0 now we sub slope(m) = (0 - (-6) / (-3-3) slope(m) = (0 + 6) / -6 slope(m) = 6/-6 which is -1 now we use y = mx + b and find b slope(m) = -1 you can use either of your sets of points (3,-6) x = 3 and y = -6 now we sub again -6 = -1(3) + b -6 = -3 + b -6 + 3 = b -3 = b so your equation is : y = -x - 3 Do you have any questions ?
yeah can you help me on this one too?? What is the equation of the line that passes through the points (0, 5) and (2, 3)?
find the slope.. slope(m) = (y2 - y1) / (x2 - x1) (0,5) x1 = 0 and y1 = 5 (2,3) x2 = 2 and y2 = 3 now sub slope(m) = (3 - 5) / (2 - 0) can you find the slope from here ?
2?
check again.... slope(m) = -2/2 now what does -2/2 = ??
1
-1
it equals -1. So our slope = -1. now we will use y = mx + b and we are looking for b slope(m) = -1 you can use either of your set of points (2,3) x = 2 and y = 3 now we sub y = mx + b 3 = -1(2) + b can you solve for b from here ?
b=5
3 = -1(2) + b 3 = -2 + b 3 + 2 = b 5 = b correct so our equation is : y = -x + 5 Do you see how I got the equation ?
omg thanks!! can you help me with another one ??
I suppose...what ya got ?
What is the slope of the line represented by the equation below? y= -2/3x+3
In y = mx + b form, the slope is in the m position. Look at your equation....y = -2/3x + 3 what number is in the m position ?
-2/3
correct....so your slope is -2/3
another one?
lets see it :) We can work on it together
What is the slope of the line that passes through the points (1, 1) and (–1, –5)?
use the slope formula slope = (y2 - y1) / (x2 - x1) (1,1) x1 = 1 and y1 = 1 (-1,-5) x2 = -1 and y2 = -5 now sub slope = (-5 - 1) / (-1-1) can you finish and find the slope ?
hello ??
im doing it
sorry...I did not mean to rush you
3
-6/-2 = 3 you are correct...the slope is 3
see..you can do this...you are smart :)
nahh i dont think so......... can you help me with another one ?
of course
What is the equation of the line that has a slope of -1/3 and a y-intercept of 5/2?
think about it....In y = mx + b form, the m is your slope and the b is your y intercept. Can you write the equation now ?
i dont know this one
slope = -1/3 y intercept = 5/2 y = mx + b (m is your slope and b is your y int) y = -1/3x + 5/2 Do you understand ?
ohh i get it
good to hear :)
another one?
It is not really that hard...you just need to learn the formulas. Yes..I can help with another one
What is the equation of the line that passes through the points (1, 2/3) and (-1,-1)?
do i need to use this formula y = mx + b?
find the slope slope(m) = (y2 - y1) / (x2 - x1) (1,2/3) x1 = 1 and y1 = 2/3 (-1,-1) x2 = -1 and y2 = -1 time to sub slope(m) = (-1-2/3) / (-1-1) slope(m) = (-3/3 - 2/3) / (-2) slope(m) = (-5/3) / -2 slope(m) = -5/3 * - 1/2 slope(m) = 5/6 this was a little tricky because of the fraction. Look over this and see if you have any questions....then we will move one to finding the equation
typo....then we will move on to finding the equation
y=5/6x-1/6
right?
lets see.. y = mx + b slope(m) = 5/6 use wither of your sets of points (-1,-1) x = -1 and y = -1 now we sub y = mx + b -1 = 5/6(-1) + b -1 = -5/6 + b -1 + 5/6 = b -6/6 + 5/6 = b -1/6 = b your equation is : y = 5/6x - 1/6 you got it :)
thanks so much
im done thanks
no problem...glad I could help
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