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The first angle of a triangle is 10 degrees smaller than the second angle. The third angle is 10 degrees less than twice the second angle. Show that this is a right triangle.
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think of the angles as A B and C.
A=b-10
c=2b-10
A+B+C=180
that should help you solve it.
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Yeah, I get it know :) Thank you. I was taking the wrong approach before.
Wait..
I set it up as b-10+2b-10=180 3b-20=180 3b=200 b=66.67?
B=180-A-C B=180-(b-10)-(2b-10) B=180-3b-20 B=160-3b?
You forgot the third angle before : (b-10)+b+(2b-10)=180
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Oh.. 4b-20=180 4b=200 b=50?
Yep !
then I plug it in and I get my other two angles right?
Exactly :)
I got it, thank you :)
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Welcome !
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