Use substitution to determine if the given ordered pair is an element of the solution set for the system of equations. (-2, 2) 5y - 5x = 10 3x + 10 = 2y Solution Not a solution
as the problem says, substitute x and y and see if the equation works
i did i got for the 1st one, 10+10=10 and the 2nd .. -6+10=4 soo, is that not a solution?
do both answers have to be the same to be solution?
1st is 5(2)-5(-2)=10
both equations do not have to be the same, they just both have to be true
not a solution because the ordered pair does not work for both equations
See thats what i thought
@acxbox22 would you care to at least demonstrate that assessment?
So its a solution?
it's a solution if the x and y values make both equations true, you substitute the values and see if that's the case
Yal all have me confused lol, i thought it was not a solution
5(2)-5(-2)=10 calculate this
its 10+10=10
10+10 is equal to 20 not 10 so this doesnt work
(-2,2) would be a solution only if it worked for both equations, you already know this is not true
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