Question

HElp please Medal

Rectangle A has an area of 9 - x2. Rectangle B has an area of x2 + x - 12. In simplest form, what is the ratio of the area of Rectangle A to the area of Rectangle B? Show your work.

Answer 1

(9-x^2) / (x^2 + x -12)
(3 + x) (3 - x) / (x + 4)(x - 3)
taking out the negative sign from (3 - x) gives - (3 + x)(x - 3)
then cancel the ( x - 3 )

-(x+3)/(x+4) is the answer.

Answer 2

Oh sure, if I know how to solve it :)

Answer 3

120r^3 / sq rt (16r^9)
= 120r^3 / 4r^4 sq rt r
= 30 / r sq rt r
rationalize the denominator
30 sqrt r/r^2

Answer 4

Your welcome :)

Answer 5

(3 + x) (3 - x) / (x + 4)(x - 3)

(3 - x) = (-x + 3 ) = - ( x - 3 )

Therefore
-( 3 + x) ( x - 3 ) / (x + 4)(x - 3)

Answer 6

You may get reported by a moderator

Answer 7

You are medal fishing and typing answers