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OpenStudy (xmoses1):
OpenStudy (anonymous):
please help me and ill help u
OpenStudy (xmoses1):
ok :) if i know how to help you lol
OpenStudy (xmoses1):
@surjithayer do you know how to do this?
OpenStudy (anonymous):
3d/c^3
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OpenStudy (xmoses1):
how did you so that?
OpenStudy (xmoses1):
*do lol
OpenStudy (xmoses1):
@jim_thompson5910 I need you to explain this to me please
jimthompson5910 (jim_thompson5910):
what is 27/9 equal to?
OpenStudy (xmoses1):
3/1 right?
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jimthompson5910 (jim_thompson5910):
or just 3
OpenStudy (xmoses1):
oh ok
jimthompson5910 (jim_thompson5910):
now we reduce the variable terms
jimthompson5910 (jim_thompson5910):
to simplify c^4/c^7, we subtract exponents (large - small)
so,
7 - 4 = 3
Because the larger exponent is in the bottom, this means that c^3 will be in the denominator
OpenStudy (xmoses1):
yeah im with you so far
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jimthompson5910 (jim_thompson5910):
for the d terms
subtract exponents (large - small): 5 - 4 = 1
Since d^5 is in the numerator and it has a larger exponent, this means d^1 or just d is in the numerator
OpenStudy (xmoses1):
so the answer should be 3c^3/d?
jimthompson5910 (jim_thompson5910):
so we have 3 and d in the numerator, 1 and c^3 in the denominator
so that's why the answer is
3d
-------
1c^3
which becomes
3d
-------
c^3