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f(x) = 4|x + 1| - 6 What is the vertex of the graph of f(x)? (-1, -6) (1, -6) (4, -6)<==My answer
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hint: in general y = a|x-h| + k has the vertex (h,k)
and it may help to think of x+1 as x - (-1)
So (4,-6) is right?
f(x) = 4|x + 1| - 6 y = 4|x + 1| - 6 y = 4|x - (-1)| - 6 What are 'a', h and k?
a= 4, h= 1, -(-1), k=-6
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h = -1 actually
if we had |x-1|, then h = 1 but we have |x-(-1)| instead, so that's why h = -1
The vertex is (h,k), so because h = -1, k = -6, the vertex is (-1,-6)
okay that makes sense! THanks!
I'm glad it does, yw
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