Am i correct? : How many complex roots does 6x4 + x3 5 = 0 have? (Points : 4) 3 4 (5) 6
what is the degree of 6x^4 + x^3 - 5
4
6
forgot x^3
degree = largest exponent
that would be 4 = 6x^4 + x^3 - 5 = 0
yes, degree = 4
so by the fundamental theorem of algebra, there are 4 complex roots the fundamental theorem of algebra says that if the degree of a polynomial is n, then there are n complex roots
ok so that how many complex roots? i thought i would have to factor to find out with synth. div.
example: 7x^3 - 5 has 3 complex roots
They just want to know how many roots. Not the actual roots.
oh i was just going to see how many would show up using the table
The number of real roots is 2. The number of complex roots is 2.
ok
The degree of the polynomial has no relationship to the number of complex roots it has.
That's the confusing nature of "complex". All real numbers are complex numbers since they are the form a+0i However, sometimes when we say "complex" we strictly mean something in the form a+bi where b is nonzero
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