Am i correct? :
How many complex roots does 6x4 + x3 5 = 0 have?
(Points : 4)
3
4
(5)
6
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jimthompson5910 (jim_thompson5910):
what is the degree of 6x^4 + x^3 - 5
OpenStudy (anonymous):
4
OpenStudy (anonymous):
6
OpenStudy (anonymous):
forgot x^3
jimthompson5910 (jim_thompson5910):
degree = largest exponent
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OpenStudy (anonymous):
that would be 4 = 6x^4 + x^3 - 5 = 0
jimthompson5910 (jim_thompson5910):
yes, degree = 4
jimthompson5910 (jim_thompson5910):
so by the fundamental theorem of algebra, there are 4 complex roots
the fundamental theorem of algebra says that if the degree of a polynomial is n, then there are n complex roots
OpenStudy (anonymous):
ok so that how many complex roots? i thought i would have to factor to find out with synth. div.
jimthompson5910 (jim_thompson5910):
example: 7x^3 - 5 has 3 complex roots
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jimthompson5910 (jim_thompson5910):
They just want to know how many roots. Not the actual roots.
OpenStudy (anonymous):
oh i was just going to see how many would show up using the table
OpenStudy (mertsj):
The number of real roots is 2. The number of complex roots is 2.
OpenStudy (anonymous):
ok
OpenStudy (mertsj):
The degree of the polynomial has no relationship to the number of complex roots it has.
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jimthompson5910 (jim_thompson5910):
That's the confusing nature of "complex". All real numbers are complex numbers since they are the form a+0i
However, sometimes when we say "complex" we strictly mean something in the form a+bi where b is nonzero