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Mathematics 7 Online
OpenStudy (anonymous):

Am i correct? : How many complex roots does 6x4 + x3 5 = 0 have? (Points : 4) 3 4 (5) 6

jimthompson5910 (jim_thompson5910):

what is the degree of 6x^4 + x^3 - 5

OpenStudy (anonymous):

4

OpenStudy (anonymous):

6

OpenStudy (anonymous):

forgot x^3

jimthompson5910 (jim_thompson5910):

degree = largest exponent

OpenStudy (anonymous):

that would be 4 = 6x^4 + x^3 - 5 = 0

jimthompson5910 (jim_thompson5910):

yes, degree = 4

jimthompson5910 (jim_thompson5910):

so by the fundamental theorem of algebra, there are 4 complex roots the fundamental theorem of algebra says that if the degree of a polynomial is n, then there are n complex roots

OpenStudy (anonymous):

ok so that how many complex roots? i thought i would have to factor to find out with synth. div.

jimthompson5910 (jim_thompson5910):

example: 7x^3 - 5 has 3 complex roots

jimthompson5910 (jim_thompson5910):

They just want to know how many roots. Not the actual roots.

OpenStudy (anonymous):

oh i was just going to see how many would show up using the table

OpenStudy (mertsj):

The number of real roots is 2. The number of complex roots is 2.

OpenStudy (anonymous):

ok

OpenStudy (mertsj):

The degree of the polynomial has no relationship to the number of complex roots it has.

jimthompson5910 (jim_thompson5910):

That's the confusing nature of "complex". All real numbers are complex numbers since they are the form a+0i However, sometimes when we say "complex" we strictly mean something in the form a+bi where b is nonzero

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