Question

Find a polynomial f(x) of degree 3 that has the following zeros.

8,-1,0

Leave your answer in factored form.

Answer 1

(x-8)(x+1)(x) = 0

now do the multiplication to get polynomial

Answer 2

The easy thing about leaving it in factored form is that you can just plug in the 3 numbers you have...

your polynomial breaks down into

(x - 8)(x + 1)(x) = 0

Because as you can see...you can plug in...8....or -1...or 0....and that entire equation will still = 0

Since this question states to leave it in factored form...you are done here

Answer 3

f(x)=x(x-8)(x+1)

Answer 4

x^3-7x^2-8x=0

Would I get this?