Question

What is the value of the expression when a = –6 and b = 5?
(a+4b)^2+2a^2

A. –1061
B. 124
C. 268
D. –311

Answer 1

so what do you think would be the first step?

Answer 2

i already did the equation and i got 340 but thats not an answer choice.

Answer 3

plug in -6 for a and 5 for b

Answer 4

i know, i did that.

Answer 5

(-6+4(5))^2+(2(-6))^2

Answer 6

Just plug in,

(a+4b)^2+2a^2
(-6+4(5))^2+2(-6)^2

(-6 + 20)^2 + -12^2
-6^2 + 20^2 + 144

36 + 400 + 144 = 580

Answer 7

Does that make sense @queenleviosa

Answer 8

(-6+20)^2+(-12)^2

Answer 9

(14)^2+(-12)^2

Answer 10

yes i know how to do the problem but the answers i get are not in the answer choices.

Answer 11

196+144=?

Answer 12

I see the mistake you did you added -6 + 20 = 14

14^2 = 196

The thing is that you have to distribute the ^2 to both numbers inside the parenthesis.

Answer 13

oh wow so i got 340 and it is not one of the choices! hmm let me try again hold on

Answer 14

Is 268 an option? I made a typo.

Answer 15

ok so the answer is 268 :)

Answer 16

oh like @tHe_FiZiCx99 said lol

Answer 17

The answer is C. 268.

Answer 18

how did u get that answer?

Answer 19

you must distribute the ^2 to each term

Answer 20

oh ok i got it now, thanks.

Answer 21

yep np :)

Answer 22

medal?