Question

What is the oblique asymptote at (4x^2)/(2x-1)? I tried 2x+1 but it was wrong. Correct answer gets a medal.

Answer 1

So for the slant asymptote yes you do the long division....but is that the correct answer?

When you divide you get 2x + 1 yes...but notice there is a remainder...you put that remainder over the original divisor.

Answer 2

Ok, what is the remainder? I have -1.

Answer 3

you have 1 (remember that you are subtracting...)

you come down to

2x
-(2x - 1)
---------
+1

So that goes over the original divisor which was 2x - 1

so altogether we have

2x + 1 + (1/(2x - 1))

Answer 4

ok thanks

Answer 5

no problem!