help with systems of equations ! solve x + 2y = 13 4x + 8y = -9
@jim_thompson5910
There are to ways to solve. Substitution or elimination. Which way do u want to use?
elimination!!
wait a sec is it 3,5 ?
No, that's not correct. So for elimination, the first thing I want to do is multiply 4 on both sides in the first equation
ok
4x + 8y = 52
and when you add you get 8x + 16y = 43
Then u want to subtract the 2 equations
isn't it add
No, u subtract. If u want to add, u can multiply one of the equaions by -1. Whether u add or subtract, ur goal is to try to elimate one of the variables
ok.. so i got 61
actually 0x + 0y = 61
Correct. Which is also 0=61. And since this isn't true, then this system of equaions has no solutions which means that they are parallel lines
so the answer is no solutions.
Correct. Because 0 doesn't not equal 61
ok thanks
No problem
i have a couple more i don't need you to do the whole thing because i know its long but i just need to know what to multiply the first equation by ,
like this one 3x - 5y = 17 9x - 15y = -4
do i multiply 9 to both sides of the first one ?
Ok. So u can look at the x's. one has a 3 and the other has a 9. In order to get rid of them, u would have to make them =. Since 3x3=9, u can just multiply the first equation both sides by 3
ahh so the goal is to get opposite coefficients
then we add or subtract ?
Becuz after multiplying, u have 9x and 9x and in order to make it=0 u would have to subtract. So in this case, u would subtract
ok thanks
ok i think im stuck i got -30y = 13
I think u did something wrong 9x-15y=51 - (9x-15y=-4) ------------------ 0x+0y=55 So 0=55
wow.
you're so smart lol
so its no solution again ?
Haha. Thanks. And yes, no solution is correct
are these hard for you
Not really especially compared to what I'm doing now
calculus
No, geometry h
oh ok
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