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Mathematics 17 Online
OpenStudy (ksaimouli):

find the coordinates of the point p on the line L1

OpenStudy (ksaimouli):

OpenStudy (anonymous):

What is L2? Could you maybe draw a clearer picture?

OpenStudy (ksaimouli):

the figure shows a line L1 in space and a second line L2, which is projection of L1 on xy plane

OpenStudy (ksaimouli):

pg 770 chp- 12, problem 37

OpenStudy (ksaimouli):

@hartnn

OpenStudy (ksaimouli):

in pdf it is last page

OpenStudy (ksaimouli):

This is something to do with projections

OpenStudy (anonymous):

okay, so first take a rule and go straight down from p all the way to L2. The intersection point will give you x, y coords.

OpenStudy (anonymous):

then take a ruler from the origin to the projection of P. Keep the angle the same as you slide it up to P itself. Then the intersection with the z axis should be the z coord.

OpenStudy (ksaimouli):

for x,y coords z=0 so (x,4,0) right

OpenStudy (ksaimouli):

@wio " The intersection point will give you x, y coords" what point did u get, I got z=0, y=4 how to get x?

OpenStudy (anonymous):

It won't get you the z coord, since know projecting it messes with the z coord. It will only get you x and y like I said. Start at the point P and move parallel to the z axis (straight down) until you hit L2. Then look at only the xy place to find the coords.

OpenStudy (ksaimouli):

i got (2,1)

OpenStudy (anonymous):

Now you measure the distance from the intersection to P, then measure the z axis to see how many units it will be.

OpenStudy (ksaimouli):

I didn't get that @wio I got stuck here|dw:1391103742633:dw| can u draw on that plz

OpenStudy (anonymous):

|dw:1391124327069:dw|

OpenStudy (ksaimouli):

ohhh, but why cross why not straight|dw:1391132958616:dw|

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