write the equation of a line parallel to the line 2x+3y=5 and passes through the point (-2,1)

A) 2x-3y=7
B) 3x-2y=7
C) 3x+2y=5
D) 2x+37=-1

Question

write the equation of a line parallel to the line 2x+3y=5 and passes through the point (-2,1)

A) 2x-3y=7
B) 3x-2y=7
C) 3x+2y=5
D) 2x+37=-1

ranga · Answer

Put the given equation in slope-intercept form and find the slope.
Parallel lines have the same slope.
Plug the slope value m in: y = mx + b
Since it passes through (-2,1), put x = -2 and y = 1 and solve for b.

anonymous · Answer

I got y=2x+5, but it doesn't appear to be in the right form. Could you help me on converting it?

ranga · Answer

2x+3y=5
3y = -2x + 5
y = -2/3x + 5/3
slope = -2/3

Parallel line will have the same slope.
y = -2/3x + b
passes through (-2,1)
1 = -2/3(-2) + b
1 = 4/3 + b
b = 1-4/3 = -1/3
y = -2/3x - 1/3
multiply by 3
3y = -2x - 1
2x + 3y = -1