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PLEASE HELP!!!!!!! Find the equation of the line below. Arrange your answer in the form y = mx + b, where b is the constant.
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To put this in the form of y = mx + b, where m is the slope, and b is the y-intercept (where the line crosses the y-axis), you must first find the slope. The first step is to solve the slope of the line, that is found by taking y2-y1/x2 - x1 **(Take y2, which is 2, and subtract -2, and you take x2, which is 2, and subtract -2)** 2-(-2) =4 2-(-2) = 4 which gives you 4/4, or 1. So your slope is 1. Next you find the point where the line crosses the y-axis, which is 0. Therefore your b = 0. This means your slope is y = x + 0, or, just y = x. Hope that helps.
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