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Physics 16 Online
OpenStudy (anonymous):

Physics Review Questions. Please help quickly!! Will give medal to best answer! A pitcher exerts 100.0 N of force on a ball with a velocity of 45 m/s. What is the pitcher's power? A 50.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45 degrees with the mast. How much work did he do? An inclined plane is 5.00 m long and 2.00 m high. What is the ideal mechanical advantage of this machine? A sailboat moves north for a distance of 10.00 km when blown by a wind 30 degrees east of south with a force of 5.00 x 10^4 N. How much work was done by the wind?

OpenStudy (anonymous):

@petiteme

OpenStudy (anonymous):

@sheelo73mughal

OpenStudy (anonymous):

For the first question I think it might be 2.2 W and for the second I think it might be 1.00 x 10^3 J?

OpenStudy (petiteme):

For the first one...Power = force x velocity :D

OpenStudy (anonymous):

so 4,500?

OpenStudy (anonymous):

@petiteme ?

OpenStudy (petiteme):

Good job! ^_^

OpenStudy (anonymous):

great! now for the second question

OpenStudy (anonymous):

would it be 50.0 x 28.3 x cos45?

OpenStudy (petiteme):

What formula did you use?

OpenStudy (petiteme):

You used... Work = Force x Displacement x Cosine(theta)

OpenStudy (anonymous):

force x distance x cos theta I think

OpenStudy (petiteme):

But 50.0 is just the mass right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

force = mass x acceleration?

OpenStudy (petiteme):

And Force = mass x acceleration

OpenStudy (petiteme):

Yes! Good job :D

OpenStudy (anonymous):

cool! So, it would be 50.0 x 9.8m/s?

OpenStudy (petiteme):

Yes :)

OpenStudy (anonymous):

so 490 x 28.3 x cos45?

OpenStudy (petiteme):

Yes :)

OpenStudy (anonymous):

9805?

OpenStudy (anonymous):

@petiteme

OpenStudy (petiteme):

Lemme get my calculator :D

OpenStudy (petiteme):

Good job! Don't forget the significant figures. It might be needed. Lol ^_^

OpenStudy (anonymous):

thanks! ok next question

OpenStudy (anonymous):

would it be 5.00/2.00?

OpenStudy (petiteme):

Inclined plane formula is length/height

OpenStudy (petiteme):

So yes ^_^

OpenStudy (anonymous):

cool so that would be 2.5?

OpenStudy (petiteme):

Good job ^_^ 2.50 to be exact. Hehehe

OpenStudy (anonymous):

haha! :) cool

OpenStudy (petiteme):

You got the last question?

OpenStudy (anonymous):

would I use the work formula?

OpenStudy (anonymous):

@petiteme

OpenStudy (petiteme):

Yes :)

OpenStudy (petiteme):

Tell me what you got ^_^

OpenStudy (anonymous):

433012.70?

OpenStudy (petiteme):

Yep :D But significant figures again. Lol. Hey, don't forget the units ^_^ Good job! :D

OpenStudy (anonymous):

oh ok lol

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