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Mathematics 11 Online
OpenStudy (anonymous):

How does the zero product property help you find the x-intercept of y = x² - x - 12?

OpenStudy (anonymous):

An \(x\)-intercept is a point on a curve of the form \((x,0)\). In terms of the equation, you let \(y=0\), then solve for \(x\): \[0=x^2-x-12~~\Rightarrow~~0=(x-4)(x+3)\] The zero product property tells you that you get \[\begin{cases}x-4=0\\x+3=0\end{cases}\]

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