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Simplify square root of 2 multiplied by the cube root of 2.
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\[\LARGE 2^{ \frac{ 1 }{ 2 } } *2^{\frac{ 1 }{ 3 }} = 2^{ \frac{ 1 }{ 6 }} =\sqrt[6]{2}\]
√2 * 3^√2 2^1/2 * 2^1/3 = 1 / 6 2^1/6 6√2^1 = 6√2
oops actually that's incorrect
let me redo that
\[\LARGE 2^{ \frac{ 1 }{ 2 } } *2^{\frac{ 1 }{ 3 }} = 2^{ \frac{ 1 }{ 2 }+\frac{ 1 }{ 3 }} =2^{\frac{ 5 }{ 6 }}=\sqrt[6]{2^{5}}\]
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The same base >.<
you need to add the exponents, not multiply them, sorry for the confusion
yes it's the same base, but that doens;t matter, look, \( \large 2^{3}*2^{4} =2^{7} \) right? not \( \large 2^{12} \)
the same logic applies to roots
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