Question

In terms of sinx and cosx only, sinxtanx + cosx =

Answer 1

\[\Large\bf\sf \sin x \tan x+ \cos x\]
\[\Large\bf\sf \sin x\frac{\sin x}{\cos x}+\cos x\]
Understand that first step?
From here, multiply the sines, then get a common denominator so you can add the terms together.

Answer 2

continue...
\[(\sin ^{2}x + \cos ^{2}x)/ cosx\]
pythagorean identity
\[((1 - \cos^2x) + \cos^2x)/cosx\]
\[1/cosx\]