Question

PLEASE HELP
is this a legitimate funcion?
f(x)=11x+5
HOW DO I SOLVE IT????????!!?!?!?!?!

Answer 1

you don't it's a function, not an equation.

Answer 2

Sure it's a legitimate function because each input you plug in for x produces exactly one output for y or f(x)

As for solving it, are you asking how to find the x-intercept?

Answer 3

To find the inverse, you replace f(x) with y. Then you swap x and y. Then solve for y.

\[\Large f(x)=11x+5\]


\[\Large y=11x+5\]


\[\Large x=11y+5\]


\[\Large x-5=11y\]


\[\Large 11y=x-5\]


\[\Large y=\frac{x-5}{11}\]


\[\Large f^{-1}(x)=\frac{x-5}{11}\]

Answer 4

If you want to evaluate f(3), then replace x with 3 in f(x) to get...

f(x) = 11x + 5

f(3) = 11(3) + 5

f(3) = 33 + 5

f(3) = 38

Answer 5

Evaluating \(\Large f^{-1}(3)\) is done the same way (but using the inverse this time)


\[\Large f^{-1}(x)=\frac{x-5}{11}\]


\[\Large f^{-1}(3)=\frac{3-5}{11}\]


\[\Large f^{-1}(3)=-\frac{2}{11}\]

Answer 6

sure thing

the last bit you need to do is plug in any number for x into f(x)

then take that result and plug it into the inverse

Answer 7

I'm glad things are clicking now