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Mathematics 20 Online
OpenStudy (ksaimouli):

show that

OpenStudy (ksaimouli):

i.j=j.k=k.i=0

OpenStudy (anonymous):

\[ \mathbf i = \langle 1,0,0\rangle, \mathbf j = \langle 0,1,0\rangle, \mathbf k = \langle 0,0,1\rangle \]So \[ \mathbf i \cdot \mathbf j = \langle 1,0,0\rangle \cdot \langle 0,1,0\rangle = 0+0+0 =0 \]

OpenStudy (anonymous):

Same thing for all other dot products.

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