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Limits help
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\[\Large If~~ \mathbb{f}~~and~~\mathbb{g}~~are~~continuous~~functions~~with~~\] \[\LARGE \mathbb{f(2)=3}~and\] \[\LARGE\lim_{x \rightarrow }~[3f(x)-g(x)]=5\] \[\LARGE \mathbb{find~~g(2)}\]
That's suppose to be x->2
use limits law
Lim x->a [f(x) + g(x)] = limx->a f(x) + lim x-> a g(x)
So based on that .. \[\LARGE \lim_{x \rightarrow 2}~g(2)=4\]
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3f(x) - 5 3(3) - 5 = 4 yep
Alright, thanks again~
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