evaluate the indefinite integral of 3(cscx times cotx)dx? (the integral for cscx times cotx is -cscx +c)

Question

anonymous · Answer

would the answer be -3cscx + c or -3cscx + 3c?

zepdrix · Answer

Either answer is acceptable.
Since c is arbitrary ( can take on any value ), 3 times an an arbitrary value is still arbitrary.

Just absorb the 3 into the c.
$\Large\bf\sf -3\csc x+3c\quad=\quad -3\csc x+c_1$

anonymous · Answer

ok. thank you again. is there a way to write an equation besides the button below the post box? I try to ask questions in the ask a question blank in the upper-left-hand corner of the screen, but I can never plug in an equation and have to use words, which are a poor substitute for the problem itself.

zepdrix · Answer

After you initially ask the question, you can go back and "edit" the post with equation tool I think.

But if you would rather understand the formatting a little bit better, you can:

`$$ put code inside of these brackets$$`

For example, to have done your question you could type:
`$$ \int 3(\csc x\cot x)dx$$`

zepdrix · Answer

If that's too confusing, maybe just try to see if it will edit your post with equation tool.

anonymous · Answer

ok. thank you yet again for helping a brudda out! ;D
catch ya l8r!

zepdrix · Answer

:3/