Question

What exponential function is the best fit for the data in the table?

x f(x)
1 -4
3 -1
4 3

f(x) = 4(3)^x - 1 + 4

f(x) = 4(3)^x - 1 - 4

f(x) = one fourth(3)^x - 1 + 4

f(x) = one fourth(3)^x - 1 - 4

Answer 1

this (3)x is
\[\LARGE{3^x}\] ?

Answer 2

yeah

Answer 3

sorry i always forget to put those in

Answer 4

well, try to plug in 1 for every option, it doesn't work for any of them, you should get -4

Answer 5

i am so lost

Answer 6

the first option 4(3)^x - 1 + 4

Answer 7

x=1 -> 4(3)^1-1+4 = 12+3 = 15

Answer 8

2nd: 4(3)^1 - 1 - 4 = 12-5 = 7

Answer 9

3rd: 1/4(3)^1 - 1 + 4 = 3/4+3=15/4

Answer 10

4th: 1/4(3)^1 - 1 + 4=3/4+3=-17/4 it doesn't work for any of them =/

Answer 11

well. this is a badly worded question :(

Answer 12

you sure the table and the options are correct?

Answer 13

i think its 3^x-1 -4

Answer 14

oh, let's see..

Answer 15

when x=1 it work for the 2nd and 4th option, but it doesn't work for x=3 or
x=4

Answer 16

well, anyway, you can solve this kind of problem plugging in the value of x and see if the function gives you f(x)

Answer 17

I made a mistake! let me try it again

Answer 18

haha no worries

Answer 19

it really doesn't work.. x=1 makes 3^(1-1)
or 3^0 wich is equal to 1, then:
4(1)+4=8
4(1)-4=0
1/4+4=17/4
1/4-4=-15/4
none of them is equal to -4 when x=1

Answer 20

the way to solve this kind of problem is plugging in the value of x and see if it gives the correct f(x)

Answer 21

so i would plug in 1/3or4 so itd be4(3)^1/3or4 -4 +4

Answer 22

you plug in 1, 3 or 4

Answer 23

the functions are
\[\LARGE{
(something)3^{(x-1)}+something}\]

Answer 24

?

Answer 25

im thinkiong its D but im not sure

Answer 26

sorry, I don't know what is going on, hope somebody can clarify this