CAN SOMEONE PLEASE HELP ME
It's a little hard to understand the question in that format.
Haha, terribly sorry!
Using the image below, find the y value for the point that divides the line segment CD into a ratio of 4:1.
2 6.2 3 2.8
http://broward.flvs.net/webdav/assessment_images/educator_geometry/v15/module06/0604_g2_q2.jpg here is the pic
Are you sure that's the right link? Anyway, find the length of the line. You need 4+1 = 5 pieces. Find 1/5 of the length. Let's see how far you get.
here it is sorry
Okay, what is the length of the line?
What do you mean like 5 boxes?
It's a diagonal line. You can't count boxes. Anyway, I was hoping to develop a checking mechanism so we could know the easier way works. If you want to cut up \(\overline{CD}\) in to a ratio 4:1, we must travel along the line segment exactly 80% of the way. Does this make sense?
Yeah kind of
If we wanted 1:1. we would go half way, or 50% The same amount on each side. Also, 1/(1+1) = 1/2 = 0.50 = 50% If we wanted 2:1. we would go 2/3 of the way, or 66.666...% Two parts behind us and one in front. Also, 2/(2+1) = 2/3 = 0.666... = 66.666...% If we wanted 3:1. we would go 3/4 of the way, or 75% Three parts behind us and one in front. Also, 3/(3+1) = 3/4 = 0.75 = 75% If we wanted 4:1. we would go 4/5 of the way, or 80% Four parts behind us and one in front. Also, 4/(4+1) = 4/5 = 0.80 = 80% Are we any closer than "kind of"? :-)
Yeah lol thanks for that
What I am about to tell you may seem a little counter intuitive. Let's see if I can explain it in terms of an argument. Suppose you are in a disagreement and you two combatants decide that your opinions are equally valid. You say "12!!!" emphatically and your opponent says, stomping his foot, "16!!". Ho do you compromise, using the agreement that your opinions are equally valid?
Meet in the middle?
Excellent. Mathematically, we might do this, weight the opinions, half for you and half for your opponent. (1/2)(12) + (1/2)(16) = 6 + 8 = 14. Bear with me. We're almost there! Now, let's assume that you have a College Degree in whatever it is you are arguing about. Let's also assume that your opponent is an arrogant youth barely passing the 9th grade. Somehow, you decide that your opinion is worth 4 times the opinion of the other. How do you compromise, using the agreement that your opinion should be respected with 4 times the weight of your opponent's opinion?
Prove that you're the better one.
I think
Nice try, but your answer is too subjective. If your opponent's view is worth "1" (just one point). Your opinion is worth "4" points. (4 times the weight.) Since there are 5 total points awarded, we can WEIGHT the opinion quite simply. (4/5)(12) + (1/5)(16) = 48/5 + 16/5 = 64/5 = 12.8 Does that make any sense at all?
Ohhh okay yeah I get it
That's all we need to solve the problem. We have two points. C: (9,6) D: (5,1) Do you believe that? It's just a matter of reading and understanding the coordinate system.
Yes I see that
No the fun part. Points C and D have a disagreement. We want to travel from C toward D, but not all the way. We want to make only 80% of the trip. This will leave four pieces on C's side and one piece left on D's side of where we stop. Agreed.
Yes I am understanding now
How do we settle the disagreement between C and D, if we weight 80% toward D?
it would be 8,5?
Let's see: C: (9,6) D: (5,1) x-coordiante: (4/5)*5 + (1/5)*9 = 20/5 + 9/5 = 29/5 = 5.8 How did you get 8?
Its 6.2 , i did it backwards by accident
y-coordiante: (4/5)*1 + (1/5)*6 = 4/5 + 6/5 = 10/5 = 2 I think you are going the wrong direction and you are still trying to do it subjectively. I'm trying to convince you to trust the mathematics. If you are going from C to D, and you are making 80% of the trip, you will be closer to D when you stop. You must weight D's opinion more heavily. I don't see 8,5 or 6.2 anywhere. Please show your calculations.
I just looked at it and I thought we had to find the coordinates
See there! "I just looked at it..." Too subjective. You do have to find the coordinates. I suppose your eyeball guess of 6.2 was not far from the exactly calculated 5.8 for the x-coordinate. Actually, that's not bad. However, we can be precise. No need to estimate or eyeball. Study the calculation provided above. one gives the x-coordinate exactly and the other the exact y-coordinate. This is a more fundamental mathematical way to solve the problem, and it does so exactly. Eyeball results can be acceptable in many circumstances, but there is no need for that sort of thing when we can calculate exactly.
Oh okay I understand, sorry. 5.8 is not an option though.
oh nvm its y coordinate
You should get (5.8,2) or (29/5,2) or some other equivalent expression.
So the answer would be 2 for the y coordinate.
That's correct.
Thank you so much, do you mind helping me with a few others?
I have to see if they're correct
Please post a new thread.
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