Question

x^2+10x+21 factor completely

Answer 1

\(\large \begin{array}{cccllll}
x^2&+10x&+21\\
&\uparrow &\uparrow \\
&7+3&7\cdot 3
\end{array}\)

Answer 2

Im still not getting it. How did you got that answer?. can you explain please?

Answer 3

have you covered this factoring quadratics yet?
should be pretty obvious

Answer 4

Nope not yet, that's the next assignment I have to work on.

Answer 5

you'd end up with 2 binomials, (x + something1)(x + something2)

an the "something1" and "something2" should sum up to the middle term
and multiply to produce the last term

Answer 6

\(\large \begin{array}{cccllll}
x^2&+10x&+21\\
&\uparrow &\uparrow \\
&7+3&7\cdot 3
\end{array}\bf \implies (x+7)(x+3)\)

Answer 7

you can try multiplying the binomials, you'd end up with the original polynomial

Answer 8

ohhhhh alright I'm getting it now and you use the FOIL method right?

Answer 9

yes

Answer 10

Alright, I got it thanks you so much :)

Answer 11

yw