Question

2(x+3)-1=7x

Answer 1

I assume you want to find the "x" value.
I guess I can help you with that.
What we want to do is leave the numbers with x's on one side of the equality and the constants (numbers) on the other side, let's begin by applying distributive property there:
\[2(x+3)-1=7x\]
\[2x+6-1=7x\]
I'll sustract "2x" on both sides, so I can do what I said earlier:
\[2x+6-1-2x=7x-2x\]
simplifying the "2x" we get:
\[6-1=7x-2x\]
taking common factor "x" on the right side, and knowing that (6-1=5) we get:
\[5=x(7-2)\]
now we can operate what's inside the parenthesis, (7-2=5) so let's replace that:
\[5=5x\]
I'll divide both sides by 5 to take that "5" off the x:
\[\frac{ 5 }{ 5 }=\frac{ 5x }{ 5 }\]
simplifying we get:
\[\frac{ 5 }{ 5 }=x\]
5 divided 5 is 1, so we can replace it:
\[1=x\]
or if you like:
\[x=1\]

And that concludes the exercise.

Answer 2

Thank you soooo much! I am supposed to be graduated already but am behind because of geometry. Literally my worst subject ever. I will probably be asking tons of questions haha.

Answer 3

I'm on a holiday in Argentina right now, but I'll reply whenever I can.

Practise and understanding makes the master, my friend.

Answer 4

Thank you! I am aware, I have been practicing & trying to understand for 4 years. It frustrates me so bad haha! I can't even figure it out if it's obvious.

Answer 5

2(x+3)-1=7x
2x+6-1=7x
2x+5=7x
5=7x-2x
5=5x
x=1