Question

Which line shows the first error in the solution

Answer 1

what do you think about line 4?

Answer 2

Reasonable

Answer 3

ok... what do you think about line 5?

Answer 4

look closely \(\large \begin{array}{llll}
6x+4=3x-8&(1)\\
6x-3x+4=3x-3x-8&(2)\\
3x+4=-8&(3)\\
3x+4-4={\color{red}{ -8-4}}&(4)\\
3x={\color{red}{ -4}}&(5)\\
\cfrac{3x}{3}=-\cfrac{4}{3}&(6)\\
x=-\cfrac{4}{3}&(7)
\end{array}\)

Answer 5

line 5?

Answer 6

anything wrong with it?

Answer 7

\(\large \bf -8-4\ne -4\)

Answer 8

the didnt put the likes together?

Answer 9

well in line 4 what's being done is subtracting -4 from both sides, so that's correct
in order to "isolate" 3x on the left-hand-side

but -8-4 = -12

Answer 10

oh i get it

Answer 11

\(\large \bf -8{\color{red}{ +}}4=-4\qquad -8{\color{red}{-}}4=-12\)