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@jigglypuff314
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for the system of equations y = x^2 - 2x - 1 y = -2 you can plug in the second into the first to get -2 = x^2 - 2x - 1 so x^2 - 2x + 1 = 0 <- can you factor this? :)
b
:o
im wrong hold on
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mmm not quite :) try factoring x^2 - 2x + 1 = 0 what would you get? :)
(x-1)(x-1)=0 so x equals 1
yep :) then you can plug in 1 for x into y = x^2 - 2x - 1 and solve for y
D :)
yep :)
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yayyy :)
thank you
you're welcome :)
well good night :)
good night :) sweet dreams :)
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