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Help me find the inverse? f(x) = cube root(x/8) -4
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\(\bf \large f(x)={\color{blue}{ y}}=\sqrt[3]{\cfrac{{\color{red}{ x}}}{8}}-4\qquad inverse\implies {\color{red}{ x}}=\sqrt[3]{\cfrac{{\color{blue}{ y}}}{8}}-4\) notice, to find the "inverse relationship" all you'd do is swap about the variables then solve for "y"
try obtaining the opposites - turns into + and vice versa multiplication turns into division and vice versa so roots turn into powers and vice versa see if this works
Ok so I think the answer is f^-1(x) = 8(x + 4)^3 But the fraction in the cube root is confusing me. Is that correct?
yeah. that's correct. god job
Yay thank you!
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