Question

Given: D is the midpoint of AC, BDABDC∠≅∠. Prove ΔABD ≅ΔCBD
i need some help puting this into a two column proof.

Answer 1

@Mertsj

Answer 2

We need a picture.

Answer 3

It probably looks like this

Answer 4

your absolutly right, i posted the wrong picture :( sorry

Answer 5

that's ok

Answer 6

So we know the following

* AD = DC (Since D is the midpoint of AC, so AC is split up into two equal halves)

* angle BDA = angle BDC (given)

* BD = BD (reflexive property)

Answer 7

So we can use the SAS property of congruence to prove that triangle ADB = triangle CDB

Answer 8

That makes since :)