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Calculus1
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Help Please!(: f(x)= (x-4)/(sqrt(x)-2) g(x)= sqrt(x)+2 Why is f(x) and g(x) not the same function? why can you find the limit as x approaches 4 of f(x) by finding the limit as x approaches 4 of g(x)?
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because the domain for f(x) is all real numbers except for 4, and the domain for g(x) is all real number.
why can you find the limit as x approaches 4 of f(x) by finding the limit as x approaches 4 of g(x)? @sourwing
\[\lim_{x \rightarrow 4} = \frac{ x-4 ( \sqrt{x } + 2 )}{ (\sqrt{x} - 2) (\sqrt{x} + 2)}\]\[\lim_{x \rightarrow 4}\frac{ x -4(\sqrt{x +2)} }{ (x-4) }\] \[\lim_{x \rightarrow 4} \sqrt{x} + 2\] this is how it's happen... got it ?
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