Question

(x+6)^2+(y+3)^2=36 my answer (-6,-3);6

But how do I show work?

Answer 1

well this appears to be the equation of a circle.

the general form is

\[(x - h)^2 + (y-k)^2 = r^2\]

the centre of the circle is (h, k) and the radius is r

so when you compare your equation to the general form

you should see h = -6 and k = -3 as well as r = 6

hope it helps