If all Cobs are Cads, but not all Cords are Cads then:
A All Cords are Cobs
B Some Cords are Cobs
C No Cords are Cobs
D None of the above are true
Explain it and a medal will be given
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OpenStudy (anonymous):
B
OpenStudy (anonymous):
what is a b and c
OpenStudy (anonymous):
A=Cobs B=Cads C= Cords
OpenStudy (anonymous):
I should have said therefor some C=A
OpenStudy (anonymous):
All A=B, Not all C=B Therefore some C=A
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OpenStudy (anonymous):
Because A=B=some C
OpenStudy (anonymous):
So if some C = B, some C also equals A
OpenStudy (anonymous):
Make sense?
OpenStudy (anonymous):
i'll think about it
OpenStudy (dan815):
some cords are cobbies
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OpenStudy (zzr0ck3r):
we are told that not all cords are are cads, this does not imply that some are.
OpenStudy (zzr0ck3r):
"not all horses are bicycles"
OpenStudy (zzr0ck3r):
:)
OpenStudy (anonymous):
none of them is true
B is false if I draw it like this
|dw:1392800855469:dw|
OpenStudy (anonymous):
C is false if I draw it like this
|dw:1392801216969:dw|
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OpenStudy (anonymous):
And A is obviously false
OpenStudy (dan815):
sry should have thought about it
OpenStudy (anonymous):
actually its D, none of the above are true
because if no cords are cabs, then B is wrong
as there are possibly no cords that are cabs