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Mathematics 21 Online
OpenStudy (anonymous):

If all Cobs are Cads, but not all Cords are Cads then: A All Cords are Cobs B Some Cords are Cobs C No Cords are Cobs D None of the above are true Explain it and a medal will be given

OpenStudy (anonymous):

B

OpenStudy (anonymous):

what is a b and c

OpenStudy (anonymous):

A=Cobs B=Cads C= Cords

OpenStudy (anonymous):

I should have said therefor some C=A

OpenStudy (anonymous):

All A=B, Not all C=B Therefore some C=A

OpenStudy (anonymous):

Because A=B=some C

OpenStudy (anonymous):

So if some C = B, some C also equals A

OpenStudy (anonymous):

Make sense?

OpenStudy (anonymous):

i'll think about it

OpenStudy (dan815):

some cords are cobbies

OpenStudy (zzr0ck3r):

we are told that not all cords are are cads, this does not imply that some are.

OpenStudy (zzr0ck3r):

"not all horses are bicycles"

OpenStudy (zzr0ck3r):

:)

OpenStudy (anonymous):

none of them is true B is false if I draw it like this |dw:1392800855469:dw|

OpenStudy (anonymous):

C is false if I draw it like this |dw:1392801216969:dw|

OpenStudy (anonymous):

And A is obviously false

OpenStudy (dan815):

sry should have thought about it

OpenStudy (anonymous):

actually its D, none of the above are true because if no cords are cabs, then B is wrong as there are possibly no cords that are cabs

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