What is wrong with the following "proof" that there are no magnetic fields. By electromagnetic theory
∇.B=0 and B= ∇XA. (the error is not in these equations).

Question

What is wrong with the following "proof" that there are no magnetic fields. By electromagnetic theory
∇.B=0 and B= ∇XA. (the error is not in these equations).

anonymous · Answer

pls see the attached file..
i dont get any idea of this question, pls help

kainui · Answer

So you've tried nothing and you're all out of ideas? I can't really help you then I'm afraid.

unklerhaukus · Answer

What is A? is A conservative?

usukidoll · Answer

o-o I'm not even on there....this is like some calc iv material with analysis attached to it

anonymous · Answer

yes, A is consevative..

samgrace · Answer

There are magnetic fields in electro-magnetic theory, the only instance that could occur to be an error is the guass's law derivation of maxwell's equations as the flux passing through a sphere or Gaussian surface over a point charge:

$$\nabla . D = \rho_c             or            

\nabla.E = \rho_c/\epsilon_0 $$ 

Whereas there are no point charge equivalents with magnets, magnet always have two poles S and N. There are no natural monopoles the net flux through the surface is zero.

experimentx · Answer

the problem is in Stokes theorem. After using Divergence theorem. the surface integral is all over closed surface, You are assuming that it is not closed ... rather open surface (closed loop).
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