find the values of the remaining trigonometric functions at t from the given infromation
Hmm?
oops sorry.... for example : sint=5/13 , cos t = -12\13
OK. The remaining trig ratios are \(\tan(t), \cot (t), \sec(t), \csc (t)\). First, \(\tan(t) = \dfrac{\sin(t)}{\cos(t)}\)
oooohhh!! so i would just plug in the numbers into the triangle?
Yes, indeed!
You don't even need to draw a triangle here. It's straightaway identities. :)
Ahhh!! See I was just reading the question wrong! :)
It's only asking you the values of tan, cot, sec and csc for t.
What if they give me this : sint= -1\2, cost>0
This one is simple as well! You can use the Pythagorean Theorem.
because sin is -1/2, would cos be the square root of 3/2 ?
Yup!
YOU ARE TO AWESOME MAN!! THANK YOU!! CANT BELIEVE I DIDNT UNDERSTAND THAT! :D Thanks man :)
No sweat, bro. Now you do!
oh one more thing? they will specify a quadrant right? because it could also be -square root of 3/2
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