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a^2 +ac +ba +bc over a-b ÷ a-b
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does it help to know that \((a-b)\div (a-b)=1\)?
It is supposed to say a^2 +ac +ba +bc over a-b ÷ a-c. My fault
Is this the problem? \(\large \dfrac{a^2 + ac + ba + bc}{\frac{a-b}{a-c} }\)
If so, remember that dividing by a fraction is the same as multiplying by its reciprocal. Also, since the numerator has four terms, try factoring it by grouping.
No, but how did you do the big fraction bar?
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\dfrac is a big fraction bar \frac is a small fraction bar
Sorry, gtg.
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