What is the magnitude and direction of the electric force on an ion ++Mg placed in an electric field of magnitude 3x10^4 N/C and direction is due south.

Question

anonymous · Answer

The answer is supposedly 2e x 3x10^4, but I dont understand why 2 was used. Can anyone help with that?

schrodingers_cat · Answer

$$F =qE$$

The charge on a Mg++ has excess positive charge equal to that of two electrons.   

So, it will be twice the charge thus the answer is just 2e x 3x10^4.

anonymous · Answer

Thank you