y'+(1/t)y=3cos2t draw a direction field and find the general solution for the differential equation
I know how to solve the problem, I mainly need someone to explain how to draw a direction field?
I was typing solution this whole time and didn't realize you typed that, lol. To draw direction field, solve for y' and you get 3cos(2t) - (1/t)y. Now take a graph where the horizontal axis is the t-axis and the vertical axis is the y-axis. Take several points and plug in the value of t and y in the equation to find the slope at that point. So then draw a small line indicating the slope at each point. For example, the point (0, 0) has a slope 3 so you draw a little line that indicates a high positive slope. Keep doing that until the overall layout of the direction field is clear.
I can't tell f I was way too elaborate or just stating the obvious, lol.
familiar wid isoclines ?
thank you bagajr that was very helpful!
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