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Mathematics 16 Online
OpenStudy (anonymous):

Calculus help?

OpenStudy (anonymous):

evaluate the trigonometric integral. Integral (x^2-sin x) dx

hartnn (hartnn):

integral x^n dx is x^(n+1)/(n+1) +c that should give you integral of x^2 when you put n=2. integral of sin x dx is standard = cos x +c

OpenStudy (anonymous):

so it would be x^(2+1)/(2+1) + c +cos x + c?

hartnn (hartnn):

yes, and now you can combine those constants into one since constant say 'c' x^3/3 + cos x +c

OpenStudy (anonymous):

and that's it I don't do anything else?

hartnn (hartnn):

nopes, that would be your final answer :)

OpenStudy (anonymous):

Thank you so much

hartnn (hartnn):

if you want to verify your answer, take the derivative of your answer and see whether you get the original function back :)

OpenStudy (anonymous):

ok. I will. Thanks!

hartnn (hartnn):

your welcome ^_^

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