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Mathematics 14 Online
OpenStudy (anonymous):

Find an equation of the circle shown below. A) (x + 10)2 + (y − 10)2 = 289 B) (x − 10)2 + (y − 10)2 = 289 C) (x − 10)2 + (y + 10)2 = 289 D) (x − 10)2 + (y − 10)2 = 17

OpenStudy (anonymous):

OpenStudy (anonymous):

@bianey23 can you calculate the radius ?

OpenStudy (anonymous):

@bianey23 Come on you can do that, right ?

OpenStudy (anonymous):

Not really I dont understand

OpenStudy (anonymous):

ok @bianey23 the radius is 1/2 the distance

OpenStudy (anonymous):

the distance between tow points A(a,b) and B(c,d) is : \[d(A,B)=\sqrt{(c-a)^2+(d-b)^2}\]

OpenStudy (anonymous):

apply it and calculate the distance of the circle then 1/2 of the distance = radius

OpenStudy (anonymous):

\[(x-h)^{2}+(y-k)^{2}=r ^{2}\]

OpenStudy (anonymous):

Good

OpenStudy (anonymous):

You are looking for h,k,r right ?

OpenStudy (anonymous):

no for x,y and r

OpenStudy (anonymous):

why do you need x and y they are variables. i gave you the formula take a look you need h and r

OpenStudy (anonymous):

h and k sorry and r of course

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