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OpenStudy (anonymous):
Indefinite integral?
evaluate this indefinite integral.
Integral (1+3t) t^2 dt
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OpenStudy (anonymous):
what theorem am I supposed to use here?
OpenStudy (luigi0210):
You could take it apart and integrate separately?
\[\LARGE \int~(1+3t)~dt~*~\int~t^2~dt\]
OpenStudy (loser66):
distribute the integrand
\[\int (1+3t)(t^2) dt=\int (t^2 +3t^3)dt\]
take integral term by term.
Dat sit, why do you need a theorem to solve it?
OpenStudy (luigi0210):
^That works too xD
OpenStudy (luigi0210):
Sorry, haven't done real integrating in about a year ._.
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OpenStudy (anonymous):
I am a little confused, how did you get t^2/3 + C , I mean what happened to the "3t^2" ??
OpenStudy (anonymous):
And I'm sorry I thought I needed a theorem thats what they were telling me but I didn't know how
OpenStudy (loser66):
Ok, let me redo it for you
\[\int (1+3t)(t^2) dt=\int (t^2 +3t^3)dt\\=\frac{t^3}{3}+\frac{3t^4}{4}+C\]
OpenStudy (anonymous):
Ok now I understand. thank you!! can you help me with one more integral??
OpenStudy (loser66):
just post. I am not sure if I can help or not.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
thanks anyways!!
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