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Mathematics 7 Online
OpenStudy (anonymous):

Please check my work will give medal. (attached picture)

OpenStudy (anonymous):

jigglypuff314 (jigglypuff314):

when dividing exponents the powers subtract like x^5 / x^2 = x^3

OpenStudy (anonymous):

check them again. remember how exponents work when you divide them. also the reciprocal of a reciprocal it not itself a reciprocal.

OpenStudy (anonymous):

can you explain it to me? i understood multiplying but dividing is harder for me /:

jigglypuff314 (jigglypuff314):

dividing is just subtracting the powers like x^7 / x^4 = x^(7-4) = x^3 so a^6 / a^4 = a^(6-4) = a^2

OpenStudy (anonymous):

so for the first one would it be the first answer?

jigglypuff314 (jigglypuff314):

not quite :) because b^3 / b^2 = b^1 = b (on top)

OpenStudy (anonymous):

ohhh right oops so its the last answer?

jigglypuff314 (jigglypuff314):

yep :)

jigglypuff314 (jigglypuff314):

then for the second one it's a general rule to have no negative exponents in the denominator

OpenStudy (anonymous):

thank you (: and would the answer be the third one?

jigglypuff314 (jigglypuff314):

not quite :) the 4 should remain on top

OpenStudy (anonymous):

oh okay so can you turn the negative into a positive? because origanlly my second choice was going to be the second answer but i wasnt sure.

jigglypuff314 (jigglypuff314):

mmm it's more like y^0 = 1 so 1/ y^(-3) = y^0 / y^(-3) = y^(0-(-3)) = y^3 on top

OpenStudy (anonymous):

So would it be 4y^3 ?

jigglypuff314 (jigglypuff314):

yep :)

OpenStudy (anonymous):

thank you! do you mind helping me with two more if its no bother (:

jigglypuff314 (jigglypuff314):

sure! :)

OpenStudy (anonymous):

thank you (:

jigglypuff314 (jigglypuff314):

both are correct! :) great job! :D

OpenStudy (anonymous):

Really? haha thank you!

jigglypuff314 (jigglypuff314):

glad I could help :)

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