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algebra 2
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@agent0smith last one :)
Multiply both sides by (a+3)(a-3)
then it cancels out the (a+3) and the (a-3), right?
there are so many terms.. I think i got confused
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\[\large a + 3(a+3) = a-3\]
Is what you'd get after multiplying by (a+3)(a-3) which is equal to (a^2-9)
Now solve for a, which is easy, and check the solution by plugging it in
I keep getting stuck when trying to solve for a
this is what i got: a=9
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\[\large a + 3a+9 = a-3 \] 3a = -12
so a=-4
now to check it i plug -4 in for all the a terms in the original question?
Yep
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