Question

Using the precise (epsilon-delta) definition of a limit, Prove that the limit of x^2 as x ->0 = 0

Answer 1

Here is my work so far . . .

|x^2 - 0|
|x^2|
|x * x|
|(x-0)(x-0)|
|(x-0)^2|
|x-0|^2 < E ???

Answer 2

I mean E as in ε (epsilon).
I'm just wondering if δ should equal the square root of ε

Answer 3

Nevermind, I figured it out.