Helps pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee Find the value of sin x° and cos y°.
@agent0smith
@ganeshie8
@whpalmer4
Using the Pythagorean theorem, \(a^2+b^2=c^2\), find the length of the hypotenuse.
can you please write the steps out...I wont forget to give u a medal
@agent0smith are you going to help please
We went through this yesterday. What are the two known sides of the triangle?
4 and 3
and we dont know the hypotenuse it dosent give it
Okay. One of them is \(a\), and the other is \(b\). Figure out the value of \(c\) so that \[a^2+b^2=c^2\]
25=c2
Okay, you're getting warm. What is the value of \(c\) that makes that true?
5?
?
Yes, \(c = 5\). Good! Now we know the length of the hypotenuse.
That means our triangle now looks like this:|dw:1391654377004:dw|
Problem asks "Find the value of sin x° and cos y°. " Do you remember what SOH CAH TOA means?
alittle bit
SOH = Sin of an angle is Opposite side / Hypotenuse CAH = Cos of an angle is Adjacent side / Hypotenuse TOA = Tan of an angle is Opposite side / Adjacent side First one to do is \(\sin x\). What is the length of the opposite side from angle \(x\)?
3
Good. What is the length of the hypotenuse?
5
Excellent. Now you know everything you need to know to tell me the value of \(\sin x\). \[\sin x = \]
3/5
0.6
There we go!
Now, for all the marbles, can you figure out the value of \(\cos y\)?
I give medals for correct answers :-)
You need to identify the adjacent side to angle \(y\), then compute adjacent/hypotenuse.
3/5 again
Yes! Wasn't so hard, was it?
It was easy wow thanks can you just help me with one last one please
Sure, post it and tag me...
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