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Mathematics 14 Online
OpenStudy (anonymous):

I need help with proportions of a figure, can anybody help me.

OpenStudy (anonymous):

OpenStudy (goldphenoix):

The two polygons are similar, so the side parallel to the other side must have a 'rule'. For instance, 16/12 = ?

OpenStudy (anonymous):

I don't get what you mean. My guess is 8, but I have to show the work.

OpenStudy (anonymous):

I meant my guess is 9.

OpenStudy (goldphenoix):

|dw:1391663349144:dw|

OpenStudy (goldphenoix):

|dw:1391663413460:dw| What's 16/12?

OpenStudy (anonymous):

1.33333333...

OpenStudy (goldphenoix):

Alright. What about 32/24?

OpenStudy (anonymous):

1.33333333333...

OpenStudy (goldphenoix):

Alright. So it's safe to assume that the rule between the polygon on the left and the polygon on the right is 1.3 repeating time. Therefore, (x-1) times 1.3 repeating should give us 6.

OpenStudy (anonymous):

So, would the answer be 9. 9-1=8 8/6=1.33333333...

OpenStudy (goldphenoix):

Opps, my bad. The other way.

OpenStudy (anonymous):

So do I have it right, if so thank you so much for the help.

OpenStudy (goldphenoix):

Yeah, you're right. Good job!

OpenStudy (anonymous):

Thanks for your help.

OpenStudy (goldphenoix):

No problem, that's why I'm here. :) Now I have to do my own homework. >_>

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