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Mathematics 6 Online
OpenStudy (anonymous):

(2x+1)(x-3)=0

OpenStudy (gorv):

2x+1=0 x=-1/2 or x-3=0 x=3

OpenStudy (anonymous):

? what do you mean

OpenStudy (anonymous):

he means x = 3 or -1/2

OpenStudy (anonymous):

oh I get it

OpenStudy (anonymous):

Duh, wahts 0

OpenStudy (anonymous):

and what is x^2-12x=-36

OpenStudy (gorv):

(x-6)^2=0 x=6,6

OpenStudy (anonymous):

ok and 21-x^2=4x

OpenStudy (anonymous):

gorv please show more work instead of just giving the answer

OpenStudy (anonymous):

theloaad who are you?

OpenStudy (gorv):

@theload....plzzzz can u solve step by step

OpenStudy (anonymous):

x^2-12x=-36 you do not get 6

OpenStudy (anonymous):

the correct answer is 6

OpenStudy (anonymous):

x = 6

OpenStudy (anonymous):

and how did you get it?

OpenStudy (anonymous):

\[x ^{2}-12x+36=0 \] is what you get when you subtract 36, then you group which means it becomes \[(x-6)^{2}=0\] so x=6 when you solve

OpenStudy (gorv):

how you got (x-6)^2 @load

OpenStudy (gorv):

@theloaad

OpenStudy (anonymous):

by grouping, what adds to -12x but multiplies to positive 36.

OpenStudy (anonymous):

21-x^2=4x and what would this be then

OpenStudy (gorv):

u should show the step buddy...as u told

OpenStudy (gorv):

@theloaad

OpenStudy (anonymous):

could you explain it to me @gorv

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