Mathematics
10 Online
OpenStudy (anonymous):
Im not 100% sure how to do this:
10 < –3x + 1
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undeadknight26 (undeadknight26):
same way you did the other one...
OpenStudy (anonymous):
is it something like :
10 < –3x + 1
-1 -1
10<-2x
OpenStudy (anonymous):
no
10 < -3x + 1
-1 -1
9 < -3x...can you finish
undeadknight26 (undeadknight26):
nope lol:
10 < –3x + 1
-1 -1
undeadknight26 (undeadknight26):
same thing i did kellie XD great minds think alike :D
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OpenStudy (anonymous):
yes they do :)
OpenStudy (anonymous):
oooh ok thats what i kinda thought
OpenStudy (anonymous):
so now we have : 9 < -3x
can you find x ?
OpenStudy (anonymous):
and then 9<-3x
OpenStudy (anonymous):
hold on im figuring it out
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OpenStudy (anonymous):
Be careful with your negative
OpenStudy (anonymous):
9/-3 < -3x/-3 ?
undeadknight26 (undeadknight26):
*claps*
OpenStudy (anonymous):
One rule with inequalities...when dividing/multiplying by a negative, the inequality sign changes
OpenStudy (anonymous):
and then.... i think..... 3 > x
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OpenStudy (anonymous):
9 < -3x -- divide by -3 and change inequality sign
9/-3 > x
-3 > x
OpenStudy (anonymous):
ok i wasnt sure if if was 3 or -3
OpenStudy (anonymous):
:D thannks
OpenStudy (anonymous):
sure thing :)
undeadknight26 (undeadknight26):
o.o
Kellie is a boss :D
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OpenStudy (anonymous):
haha ikr