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How to factor 9x^2-3xy+6x-2y?
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Group the first two terms and factor out 3x Group the last two terms and factor out 2 Now you have two terms and they have the common factor 3x-y Factor it out
9x^2 - 3xy + 6x - 2y Factor by grouping: (9x^2 - 3xy) + (6x - 2y) factor out the 3x on the left, and 2 on the right 3x(3x - y) + 2(3x - y) Try to finish. There's a common factor.
9x^2 and 3xy has the common factor of 3 but 6x-2y doesn't.
and you make it so simple. you're a great teacher.
Group the first two terms and factor out 3x
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I just realized I forgot the 3x.
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